If secA-tanA=x then prove that 1/x=secA+tanA.
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Answered by
3
SecA - tanA = x
××××××××××××××××
1/x = 1/(SecA - tanA)
By rationalization,
1/x = (SecA + tanA)/(sec²A - tan²A)
We know, sec²A - tan²A = 1
1/x = secA + tanA
Hence, proved.
I hope this will help you
(-;
××××××××××××××××
1/x = 1/(SecA - tanA)
By rationalization,
1/x = (SecA + tanA)/(sec²A - tan²A)
We know, sec²A - tan²A = 1
1/x = secA + tanA
Hence, proved.
I hope this will help you
(-;
Answered by
2
This problem can be proved as shown above
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Just solve it
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