Question

If SecA= under root 10 find sinA​

Answer 1

Answer:

$\frac{3\sqrt{10} }{10}$

Step-by-step explanation:

$sec A = \frac{1}{cosA} =\sqrt{10} \\\\cosA = \frac{1}{\sqrt{10} } = \frac{\sqrt{10} }{10} \\\\sin^{2}A + cos^{2}A = 1\\\\sin^{2}A + \frac{10}{100} = 1\\\\\\sin^{2}A = \frac{100-10}{100} = \frac{90}{100}\\\\\ sinA = \sqrt{\frac{90}{100} } =\frac{3\sqrt{10} }{10}$