IF SECA=X+1/4X,THEN PROVE THAT SECA+TANA=2X OR1/2X
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Hope it will help u:-
Given - secA= x+1/4x
To prove - secA-tanA=1/2x or 2x
Prove -
sec^2-tan^2=1
sec^2A=x^2+1/16x^2+1/2
put the value
x^2+1/16x^2+1/2-1= tan^2A
x^2+1/16^2-1/2=tan^2
tan^2A=(x-1/4x)^2
tanA=x-1/4x
Put the value
SecA+tanA=x+1/4x+x-1/4x
SecA+tanA=2x
Hence prove....☺☺
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