Question

if secA = x+1/x, prove that secA+tanA = 2 x or 1/2x​
there is no problem with the question

Answer 1

Step-by-step explanation:

sec A = x + 1/(4x)

sec^2 A = 1 + tan^2 A

x^2 + 1/2 + 1/(16x^2) = 1 + tan^2 A

x^2 - 1/2 + 1/(16x^2) = tan^2 A

± [x - 1/(4x)] = tan A

sec A + tan A = x + 1/(4x) ± (x - 1/(4x)) = 2x or 1/(2x)