Question

if secant a + tan A =1/5, then find secA - tanA​

Answer 1

Answer:

( secA - tanA ) = 5

Step-by-step explanation:

we know,

sec² A - tan² A = 1

( secA + tanA ) ( secA - tanA ) = 1

[ a² - b² = ( a + b) ( a - b ) ]

1/5 × ( secA - tanA) = 1

[ Given, ( secA + tanA = 1/5 ) ]

( secA - tanA) = 5

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