Math, asked by poonam241175, 11 months ago

If secb-tan B = √2 tan B. Then show that sec B + tan B = √2sec B.

Answers

Answered by sandy1816

0

Step-by-step explanation:

secB-tanB=√2 tanB

(secB-tanB)²=(√2 tanB)²

sec²B+tan²B-2secBtanB=2tan²B

2secBtanB=tan²B-sec²B

now

(secB+tanB)²=sec²B+tan²B+2secBtanB

(secB+tanB)²=sec²B+tan²B+tan²B-sec²B

(secB+tanB)²=2sec²B

secB+tanB=√2 secB

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