Question

If seco =a+1/a-1+tano then coso is
​

Answer 1

Step-by-step explanation:

Given

$\sec \: o \: = \frac{a + 1}{a - 1 + \tan \: o }$

we know that sec o = 1/cos of

$\cos \: o \: = \: \frac{a - 1 + \tan \: o }{a + 1}$