Question

If seco + tan 0 =p, then what is the value of seco - tan
k? -]
​

Answer 1

Answer:

$\frac{1}{p}$

Step-by-step explanation:

$\sec( 0 ) + \tan(0) = p$

$we \: \: know \: \: that \: \:$

$( \sec(o) + \tan(o) )( \sec(o) - \tan(o)) = { \sec( o ) }^{2} - { \tan(o) }^{2}$

$= 1$

$( \sec( 0 ) + \tan(0) )( \sec( 0 ) + \tan(0)) = 1$

$p( \sec(o) - \tan(o) ) = 1$

$\sec(o) - \tan(o) = \frac{1}{p}$

HOPE THIS ANSWER HELPS YOU ✍✍...

PLEASE MARK IT AS BRAINLIEST...