If seco + tan0 = p, then find the value of coseco.
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Hii mates here is your answer ........
sec + tan = p
1/cos + sin /cos = p
(sin +1)/cos = p
(sin + 1)^2 /(1 - sin)^2 = p^2
(sin + 1)/ ( 1 - sin ) = p^2
sin + 1 = p^2 - p^2sin
sin + p^2 sin = p^2 -1
sin (1 + p^2) = p^2 - 1
sin = (p^2 -1) / (1+p^2)
cosec = (1 +p^2)/ (1 - p^2)
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