Question

If seco + tan0 = x then seco =
a)x²+1/x
b)x²1/x
c)x²+1/2x
d)x²-1/2x​

Answer 1

Answer:

sec²0 - tan²0 = 1

( sec0 - tan0 ) ( sec0 + tan0 ) = 1

( sec0 - tan 0 ) (x) = 1

sec0 - tan0 = 1/ x

Therefore value of sec0 - tan 0 is 1/x