If Seco + Tane = P Then find the value of Sece-Tane
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Step-by-step explanation:
Given
sec t + tan t = p
we know that sec^2 t - tan^2 t = 1
Now applying a^2 - b^2 = (a+b)(a-b)
(sec t - tan t) (sec t + tan t) = 1
sec t - tan t = 1 / sec t + tan t
So,
sec t - tan t = 1/p
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