If seco - tano = 4 then prove that cosO=8/17
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http://fleurmarsella.weebly.com/uploads/2/3/1/1/23113184/pc_12_-_trig_review_-_solutions.pdf
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solution
Sec²A-tan²A=1
=>(secA-tanA)(secA+tanA)=1
=>4(secA+tanA)=1
=>secA+tanA=1/4
now....
secA-tanA=4
secA+tanA=1/4
___________________
secA=17/8
=>cosA=1/secA=8/17
=>cosA=8/17 (proved)
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