Question

if secØ= 25/7, then sinø=?​

Answer 1

Step-by-step explanation:

Sec A = 1/CosA

CosA = 7/25

Sin^2 A + Cos^2 A = 1

Sin^2 A = 1-Cos^2 A

Sin^2 A = 1 - 49/625

Sin^2 A = 576 / 625

Sin A = 24/25

Answer 2

$\huge\frak\red{\underline{\underline{AnsWeR}}}$

$\green{\sf{\underline{\:Given}}}$

$\mapsto\sf{\:\sec \theta \:=\dfrac{25}{7}}$

$\green{\sf{\underline{\:Find}}}$

$\mapsto\sf{\:sin \theta}$

$\huge\frak\red{\underline{\underline{EXPLAnation}}}$

A/C To Picture

$\:\:\:\:\:\red{\sf{\:( In\:\triangle \:\:\:ABC ) }}$

$\:\:\:\:\:\green{\sf{\:( By\:Pythagoras\:theorem )}}$

$\large\green{\boxed{\boxed{\pink{\sf{\:(Perpendicular)^2\:=\:(Hypotenuse)^2-(base)^2}}}}}$

$\mapsto\sf{\:(AB)^2=\:(25)^2-(7)^2}$

$\mapsto\sf{\:(AB)^2\:=\:625-49}$

$\mapsto\sf{\:(AB)^2\:=\:567}$

$\mapsto\sf{\:(AB)\:=\sqrt{576}}$

$\mapsto\pink{\sf{\:(AB)\:=\:24}}$

We Have

$\:\:\:\:\:\green{\sf{\:\left(\sin \theta \:=\dfrac{perpendicular}{Hypotenuse}\right)}}$

$\mapsto\sf{\:\sin \theta \:=\dfrac{AB}{AC}}$

$\pink{\mapsto\sf{\:\sin \theta \:=\dfrac{24}{25}\:\:\:\:\:(AnS)}}$

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