Question

If secØ = 5/4, find the value of sinØ

Answer 1

Answer:

sinФ=3/5

secФ=5/4=H/B

H=5

B-4

P=?

H^2=B^2+P^2

5^2=4^2+P^2

25=16+P^2

25-16=P^2

9=P^2

√9=P

3=P

sinФ= P/H

=3/5