if secø+tanø=p, then what is the value of secø-tanø?
Answers
Answered by
0
Answer:
secθ+tanθ=p ... (1)
secθ−tanθ=
p
1
... (2)
(1) + (2)
⇒2secθ=p+
p
1
⇒secθ=
2
1
(p+
p
1
)
⇒
cosθ
1
=
2
1
(p+
p
1
)=
2
1
(
p
p
2
+1
)
⇒cosθ=(
p
2
+1
2p
)
(1) - (2)
⇒2tanθ=p−
p
1
⇒tanθ=
2
1
(p−
p
1
)
⇒
cosθ
sinθ
=
2
1
(p−
p
1
)
⇒sinθ=[
2
1
(p+
p
1
)]cosθ
⇒sinθ=
p+
p
1
p−
p
1
=
p
2
+1
p
2
−1
⇒cosecθ=
p
2
−1
p
2
+1
Similar questions