If second term of an A.P is 4 and seventh term of an A.P is -11.Find the sixteenth term
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a+d = 4
a+ 6d = -11
solving by elimination method,
-5d = 15
d = -3
a= 7
The 16term is,
7 + {-3(16-1)} = -38
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a+ 6d = -11
solving by elimination method,
-5d = 15
d = -3
a= 7
The 16term is,
7 + {-3(16-1)} = -38
How this helps.
Please mark as brainliest
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