Question

if secQ + TanQ = p then find the value cosecQ ​

Answer 1

Step-by-step explanation:

Since ,

sec^2 Q - tan^2Q=1

→(sec Q+ tanQ)(secQ-tanQ)=1

→secQ- tanQ=1/p

Now , secQ+tanQ=p

Solving the equations we get ,

secQ=(1+p^2)/2p

and ,

tan Q=(p^2-1)/2p

Now , cosecQ= secQ/tanQ=(p^2+1)/(p2-1)

Answer 2

Answer:

→ ( p^2 + 1) / ( p^2 - 1 )

Step by step explanation →

We will solve this question using some trigonometric identities .

We know sec²x - tan²x = 1

so, sec²Q - tan²Q = 1

or, (secQ - tanQ)(secQ - tanQ) = 1

or, (secQ - tanQ) = 1/(secQ + tanQ) = 1/P

now, solve equations ; secQ + tanQ = P and secQ - tanQ = 1/P

e.g., (secQ - tanQ) + (secQ + tanQ) = p + 1/p

2secQ = (p² + 1)/p

secQ = (p² + 1)/2p

cosQ = 2p/(p² + 1) = base/hypotenuse

perpendicular =

= ±(p² - 1)

so, cosecQ = hypotenuse/perpendicular

= ± (p² + 1)/(p² - 1)