If SecQ x+1/4x prove that secQ+tanQ = 2x or 1/2x
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Answer:
Step-by-step explanation:
Let’s take theta = A
Also square is represented by *
SecA = x+1/4x
S.B.S
Sec*= x*+1/16x*+1/2
We know sec^2 = 1+ tan*A
1+tan* = x* + 1/16x* +1/2
Tan*A = x* + 1/16x*+1/2-1
Tan*A = x* + 1/16x*-1/2
Tan*A = ( x- 1/4x)*
TanA = +- ( x-1/4x)
TanA = -x+1/4x , x-1/4x
So according to this
SecA + TanA = x-1/4x +x +1/4x
= 2x
Also Seca + tanA = -x+1/4x+ 1/4x+x
= 1/2x
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