IF SECtheta AND SINtheta (0<theta<90) are
THE ROOTS OF THE EQUATION
√6x square -kx+√6 =0 THEN VALUE OF IS?
Answers
Answered by
0
ANSWER
secθ+tanθ=2+
5
secθ−tanθ=
2+
5
1
=
5
+2
1
×
5
−2
5
−2
=
5
−2=
5
−2
secθ−tanθ=
5
−2⇒2secθ=2
5
secθ=
5
⇒cosθ=
5
1
sin
2
θ=1−cos
2
θ=1−(
5
1
)
2
=1−
5
1
=
5
4
⇒sinθ=
5
2
. ˢᵀᴬᵞ ˢᴬᶠᴱ
ˢᵀᴬᵞ ᴳᴼᴸᴰ
Answered by
0
Answer: 3√3
Step-by-step explanation:
√6 x²-kx+√6 = 0
product = c/a =√6/√6 =1
sin∅×sec∅ =1
∵ ∅=45°
substitute sin 45°value,
√6×1/2 - 1/√2×k + √6 =0
√3-k+2√3=0
∴ k =3√3
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