if sectheta +tan theta=1 then find sectheta -tan theta
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3
hello friend , here is your answer ,
_____________
sec²-tan²=1
and also given is
sec+tan=1
so , by formula a²-b²= (a+b)(a-b)
(sec+tan)(sec-tan)=1
1×(sec-tan)=1
sec-tan=1
_____________
_____________
sec²-tan²=1
and also given is
sec+tan=1
so , by formula a²-b²= (a+b)(a-b)
(sec+tan)(sec-tan)=1
1×(sec-tan)=1
sec-tan=1
_____________
PrateekStar1:
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Answered by
1
Sec theta + tan theta =1
Squaring on both sides
Sec^2theta + tan^2theta +2secthta tantheta=1
Sec^2theta +sec^2theta-1 +2sectheta tantheta =1
2sec^2theta+2sectheta tantheta =2
2sectheta(sectheta+tantheta)=2
Sectheta (1)=1
Therefore tantheta =0
Sectetha -tantheta =1-0=1 ans...
Hope it will help
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Squaring on both sides
Sec^2theta + tan^2theta +2secthta tantheta=1
Sec^2theta +sec^2theta-1 +2sectheta tantheta =1
2sec^2theta+2sectheta tantheta =2
2sectheta(sectheta+tantheta)=2
Sectheta (1)=1
Therefore tantheta =0
Sectetha -tantheta =1-0=1 ans...
Hope it will help
Pls mark brainliest
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