Question

If sectheta + tan theta =m and sectheta - tantheta=n show that mn=1

Answer 1

Hey mate!

Refer the attachment!

Answer 2

$\sec( \alpha ) + \tan( \alpha ) = m \\ \\ \sec( \alpha ) - \tan( \alpha ) = n$
Then

mn= (sec theta+ tan theta)(sec theta - tan theta)

mn = sec² theta - tan² theta

Siince 1+ tan²theta = sec² theta
=> 1= sec² theta -tan² theta

Then
mn = 1

Hence proved


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