if sectheta+tantheta=2,then sec theta- tan theta=?
Answers
Answered by
41
sec theta + tan theta = 2
= 1/sec theta + tan theta = 1/2
= 1/sec theta + tan theta * (sec theta - tan theta)/(sec theta - tan theta) = 1/2
= sec theta - tan theta/sec^2 theta - tan^2 theta = 1/2
Formula is ( sec^2 theta -tan^2 theta = 1)
So, sec theta - tan theta = 1/2
= 1/sec theta + tan theta = 1/2
= 1/sec theta + tan theta * (sec theta - tan theta)/(sec theta - tan theta) = 1/2
= sec theta - tan theta/sec^2 theta - tan^2 theta = 1/2
Formula is ( sec^2 theta -tan^2 theta = 1)
So, sec theta - tan theta = 1/2
teja14:
answer is wrong
Answered by
58
secα +tanα = 2
We know that sec²α-tan²α=1
This can be written as (secα-tanα)(secα+tanα)=1
Substitute the value of secα+tanα=2 in the above equation from which we get the value of secα-tanα= 1/2
HOPE U LIKED THE ANSWER :D
We know that sec²α-tan²α=1
This can be written as (secα-tanα)(secα+tanα)=1
Substitute the value of secα+tanα=2 in the above equation from which we get the value of secα-tanα= 1/2
HOPE U LIKED THE ANSWER :D
Similar questions
CBSE BOARD X,
8 months ago
English,
8 months ago
Science,
8 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago