Question

If secx = root 2 and 3pi/2 < x < 2pi find the value of 1+tanx

Answer 1

Step-by-step explanation:

secx = root 2

now, squaring on both sides, then we get..

sec square x = 2

now, we know that, sec square x = 1 + tan square x..

then, 1 + tan square x = 2

whole square of a+b= a square + b square + 2ab

a square + b square = whole square of (a+b) - 2ab...

therefore, whole square of (1+ tan) - 2tanx = 2

whole square of (1+tanx)=2+2tanx

whole square of (1+tanx)=2(1+tanx)

1+ tanx = 2