Question

If secx + Tan x=2 then find the value of cosecx+cotx
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Answer 1

Answer:

Answer 1

Step-by-step explanation:

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Answer 2

❥${\green{\underline{\underline{\huge{\mathtt{Question:-}}}}}}$

If sec x + tan x = 2 ,then find the value of cosec x + cot x.

❥${\green{\underline{\underline{\huge{\mathtt{Solution:-}}}}}}$

$sec \: x \: + tan \: x = 2 \\ = > \frac{1}{cos \: x} + \frac{sin \: x}{cos \: x} = 2 \\ = > \frac{cos \: x + sin \: x}{cos \: x} = 2 \\ = > cos \: x \: + sin \: x \: = 2cos \: x$

Now, Find the value of cosec x+ cot x.

$cosec \: x \: + \: cot \: x \\ = \frac{1}{sin \: x} + \frac{cos \: x \: }{sin \: x} \\ = \frac{sin \: x + cos \: x}{sin \: x} \\ = \frac{2cos \: x}{sin \: x}$

❥${\green{\underline{\underline{\huge{\mathtt{Answer:-}}}}}}$

cosec x + cot x = 2cos x / sin x.