Question

if secx+tanx/secx+tanx=209/79 then sinx=?

Answer 1

Left-hand-side:

1sec(x)−tan(x)1sec(x)−tan(x)

= 1sec(x)−tan(x)∗sec(x)+tan(x)sec(x)+tan(x)= 1sec(x)−tan(x)∗sec(x)+tan(x)sec(x)+tan(x)

= sec(x)+tan(x)sec2(x)−tan2(x)= sec(x)+tan(x)sec2(x)−tan2(x)

Now use 

1+tan2(x) = sec2(x)1+tan2(x) = sec2(x)

and you should be done.....

Answer 2

i dont know your answer