Question

If Secx+tanx= y then
the value of secx =?
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Answer 1

Answer:

pls stop posting all these things here

Answer 2

First of all the question is wrong
We should find sec x - tanx
Given,
sect+tanx=y
We know that
1+ tan^2x=sec^2x
So,sec^2x-tan^2x=1
Dividing both the sides by sec x+tan x
(sec^2x-tan^2x)/sec x +tan x=1/(sec x+tan x)
((sec x+ tan x)(sec x-tan x))/sec x+tan x=1/y (Given that sec x+tan x =y)
sec x-tan x=1/y
So the value of sec x-tan x is 1/y