If set A has 12 elements then the number of subsets of A having at least three elements is
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Assuming all elements of S are distinct], Then there are C(12,k) ways of picking (a subset of) k elements from S. So: [C(12,0) +] C(12,1) + C(12,2) + C(12,3) We could also include C(12,0)=1 pedantically since the empty set also qualifies (trivially)...
Parvathi2001:
I have a small doubt. As per the quedtion they asked for atleast 3 elements. Sorry to say this ,you have given the answer for atmost 3 elements. Thank you very much for spending your time on my question
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