If set of X has 50 elements and X intersection Y has 10 elements then what is Y ?
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Answered by
9
Step-by-step explanation:
Given n(X∪Y) = 50
; n(X) = 28; n(Y) = 32
But n(X∪Y) = n(x) + n(y)-n(X∩Y)
∴ n(X∩Y) = 28 + 32-50 = 10
Hope it helps.
Answered by
3
Answer:
I don't understand understand sorry
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