Question

if seu=13/5 show that sec theeta/sin theeta-tan theeta=-169/96

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

sec theta=13/5, cos theta=5/13, sin theta=√(1-cos^2 theta)=12/13, tan theta=5/12

sec theta/sin theta - tan theta=

(13/5)/(12/13) - 5/12 =169/60 - 5/12=(169 -25)/60

=144/60=12/5

If you take this way : sec theta/(sin theta-tan theta)=((13/5)/{(12/13)-(5/12)}

=(13/5)/{

=(144-65)/(13×12)}

=(13/5)/{79/(13×12)}

=13×13×12/79