If seven times the 7th term of an A.P. is equal to eleven times the 11th term, then what will be its 18th term?
Answers
Answered by
16
7(a+6d)=11(a+10d)
-4a=68d
a=-17d
(Putting a's value)
d=1
a18=a+17d
=-17+17
= 0
-4a=68d
a=-17d
(Putting a's value)
d=1
a18=a+17d
=-17+17
= 0
Answered by
8
7(a+6d)=11(a+10d)
-4a=68d
a=-17d
a18=a+17d
Now a18=-17d+17d
So a18=0
sujatha11:
If u have difficulty in doing these type of sums
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