If several capacitors are connected in series or parallel, show that the energy stored would be additive in either case.
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Given: several capacitors are connected in series or parallel.
To find: show that the energy stored would be additive in either case.
Solution:
- Now we have given that capacitors are connected in series or parallel.
- Consider parallel combination:
- In this, the voltage across each capacitor is same.
- So the energy stored in the combination of the two capacitors will be:
E = 1/2CV²
E = 1/2(C1 + C2)V²
E = 1/2C1V² + 1/2C2V²
E = E1 + E2
- Consider series combination:
- In this, the charge on each capacitor is equal.
- So the energy stored in the combination of the two capacitors will be:
E = 1/2(Q²/C)
E = Q²/2(1/C1 + 1/C2)
E = Q²/2C1 + Q²/2C2
E = E1 + E2
Answer:
So we have proved that the energy stored would be additive in either case.
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