Question

If she moves 40 m closer to the wall she finds the clapping rate has to be 80 per minute. What value do these measurements give for the speed of sound?

Answer 1

Answer:

sorry I cant answer this question

Answer 2

Answer:

Speed of Sound = 320m/s

Step-by-step explanation:

As speed of sound us constant(for some fixed circumstances, e.g temperature, pressure etc), the speed would be same for any position.

Now as the girl was standing at a distance of 160m from the hill and now she has moved 40m closer, then distance now becomes:

s = 160-40

s = 120m

Now, from the given data, it is clear that the clap rate has increased, i.e. 80 claps/min; thus, time taken is reduced.

Time taken by the sound to travel form the source(girl) to the hill(form where the sound strikes and echo is produced) = 60/80 = 3/4 seconds.

Which is due to the fact that she makes exactly 80 claps, time taken would be: 60/clap rate(which is 80)

Now, as the speed can be calculated as:

s = vt

v = s/t --(i)

Now, the distance travelled by that sound wave(travelling from girl to the hill and striking back to the girl to produce echo) will be 2 times the distance between girl and hill which is '120m'.

Thus,

s = 2 × 120

s = 240m

Now, eq(i) =>

v = s/t

v = 240/(3/4)

v = 320 m/s.