Question

If side of a sqaure is (x+3y) units then the area of sqaure ​

Answer 1

Step-by-step explanation:

Given:-

the side of a square is=(x+3y)

To find:-

Area

Solution:-

Here a=(x+3y)

As we know in a square

$\large{\boxed{Area={a}^{2}}}$

$= > area = {(x + 3y)}^{2} \\ = {x }^{2} + 2 \times x \times 3y + {3y}^{2} \\ = {x}^{2} + 6xy + {9y}^{2}$

Hence your answer is

${\boxed{{x}^{2}+6xy+{9y}^{2}}}$