If side of a square reduced by 25% in decrease percentage of its area and perimeter•find it
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Let the side of the given square be x, then its area is x^2.
When the side is decreased by 20%, new side is x(100–20)/100=x*80/100=0.8x
Area of the new square=(0.8x)^2= 0.64x^2
Difference in areas is =x^2–0.64x^2=0.36x^2
Percentage decrease =(0.36x^2/x^2)*100=0.36*100=36%
I hope it help ya. Have a good day/night ahead dear~
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