If side of an equilateral triangle is x units what is its height
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Answered by
1
Step-by-step explanation:
draw a median to the triangle ABC. let the median be AD.
now ABD is. a right triangle where AB = x, BD = 1/2BC
BD = x/2
AD is the height
by Pythagoras theorem,
AD square + BD square = AB square
AD square = x square - x/2 square
= x square - xsquare / 4
= 4x square - x square /4
= 3 x square / 4
AD = √3x / 2 units
Answered by
1
Step-by-step explanation:
Side of equilateral triangle = X units
Take equilateral triangle ABC
Draw a median D to BC
In triangle ABD:
AB^2 = AD^2 + BD^2
x^2 = AD^2 + (x/2)^2
x^2 = AD^2 + x^2/4
x^2 - x^2/4 = AD^2
4x^2/4 - x^2/4 = AD^2
3x^2/4 = AD^2
AD = root3x/ 2
Hope it helps you
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