Question

if side of isosceles is 14 cm then what is it's area?​

Answer 1

Answer:

Step-by-step explanation:

Let sides are 5x, 5x and 4x.  

Therefore, 5x+5x+4x = 14  

14x= 14  

x=1  

Therefore sides are 5cm, 5cm and 4cm.  

S= a+b+c/2 = 5+5+4/2 = 7  

Area= √ s(s-a)(s-b)(s-c)  

=√ 7(7-5)(7-5)(7-4)  

=√ 7x 2x 2x 3  

2√21

hope it helps u..

Answer 2

Answer:

If it is a right isosceles triangle area is 98 cm^2

Step-by-step explanation:

Area of the triangle is

$1 \div 2 \times b \times h$

ATQ

-------

side is 14 base and height is 14

1/2 × b× h u^2

= 1/2 × 14×14 cm^2

= 7×14 cm^2

= 98 cm^2

Hope you get the answer of this question

please mark me as brainliest