if side of square is decreased by 3 times its area is decreased by
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For square
Area = (Side)²
A₂/A₁ = (S₂/S₁)²
A₂ = A₁ × [(2S₁/3) / (S₁)]² ……[∵ Final Side = S₁ - S₁/3 = 2S₁/3]
A₂ = 4A₁/9
Decrease in area = A₁ - A₂ = A₁ - 4A₁/9 = 5A₁/9
∴ Area is decreased by 5/9
Area = (Side)²
A₂/A₁ = (S₂/S₁)²
A₂ = A₁ × [(2S₁/3) / (S₁)]² ……[∵ Final Side = S₁ - S₁/3 = 2S₁/3]
A₂ = 4A₁/9
Decrease in area = A₁ - A₂ = A₁ - 4A₁/9 = 5A₁/9
∴ Area is decreased by 5/9
riddhi24:
wrong
Answer edited.
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4
No I have answered in previous one ok I m telling once again ...now see the area after decreasing side by 3 Times area also decreases by 8/9 times
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It’s wrong. Side is decreased “by” 3 times. It means final side is 2/3 times initial side.
Side length (S) decreased “by” 1/3 times means final side length = 2S/3 and Side length (S) decreased “to” 1/3 times means final side length = S/3
Leave it. You’ll understand it in your higher classes.
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