If sides are 9m, 11m and 12m. What is the area?
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Answer:
8√70 m²
Step-by-step explanation:
Sides of the triangle = 9m, 11m, 12m
Area of the triangle = √s(s - a) (s - b) (s - c) square units
a, b, c are 9m, 11m, 12m respectively
s = (a + b + c)/2
= (9 + 11 + 12)/2
= 32/2
= 16m
Area of the triangle = √16(16 - 9)(16 - 11)(16 - 12) square units
= √16 × 7 × 5 × 8
= 4 × 2 × √70
= 8√70 m²
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