Math, asked by farhan05ashraf, 8 months ago

If sides of a triangle are (2a + 4), (4b + 3) and (2c-1) then find the Semi-perimeter of the triangle.​

Answers

Answered by Anonymous
4

 \dashrightarrow\bf \:  \frac{(2a + 4) + (4b + 3) + (2c - 1)}{2}  \\  \bf  \to \: \:  \frac{2a + 4b + 2c + 4 + 3 - 1}{2}  \\  \bf \to \:  \frac{2a + 4b + 2c + 6 }{2}  \to \: ans.

Answered by khanramsha1293
2

Answer:

a+2b+c+3

Step-by-step explanation:

semi perimeter of triangle = a+b+c/2

a=2a+4

b=4b+3

c=2c-1

semi perimeter of triangle=2a+4+4b+3+2c-1/2

=2a+4b+2c+6/2

=2(a+2b+c+3)/2

=a+2b+c+3

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