Question

If sides of a triangle are 4,5,6 then prove that the largest angle is equal to twice the smallest angle

Answer 1

Answer:

Step-by-step explanation:

Let the sides of a Δ are in the ratios of 4x, 5x,6x

We know that 4x+5x+6x=180° (Sum of Δ Properties)

Therefore : 4x+5x+6x=180°

15x=180°

X= 180/15

X=12°

So angles of Δ are=

4x= 4x12=48

5x= 5x12=60

6x= 6x12=72