Question

if sides of equilateral triangle is half then find the ratio of new triangle and given Triangle​

Answer 1

Step-by-step explanation:

I AM PRETTY SURE THAT IT IS TUFF TO FIND OUT THE ANSWER.

I TRIED MY LEVEL BEST BUT I COULDN'T. I AM JUST IN 7TH AND HOW DO YOU EXPECT ME TO ANSWER THIS ONE????

Answer 2

Answer:

The ratio of new triangle and given triangle​ = 4

Step-by-step explanation:

As per the question,

We know that equilateral triangle is a triangle having all sides are equal .

Let us consider ΔABC is an equilateral triangle,such that the sides

AB = BC = AC = x

Area of an equilateral Δ is given by = $\frac{\sqrt{3} }{4 } a^{2}$

     ∴    Area of an equilateral ΔABC  = $\frac{\sqrt{3} }{4 } x^{2}$

Now, according to question , if sides of equilateral triangle is half,

Therefore new triangle is ΔA'B'C' having new sides are AB' = BC' = AC' which is equal to half of original sides.

∴ AB' = BC' = AC' = x/2

∴   Area of a new equilateral ΔA'B'C'  = $[tex]\frac{\sqrt{3} }{4 } (\frac{x}{2} )^{2}$[/tex]

                                                              = $\frac{\sqrt{3} }{16 } (x)^{2}$

Therefore , ratio = new triangle/given triangle

                           = $\frac{\sqrt{3} }{4 } x^{2}$/$\frac{\sqrt{3} }{16 } (x)^{2}$

                           = 4

Hence, the ratio of new triangle and given triangle​ = 4