Math, asked by rabindrarai712, 10 months ago

If simple interest and compound interest of a certain sum of money for two years are ₹8400 and ₹8652, then let us write by calculating the sum of money and the rate of interest.

Answers

Answered by tahseen619
43

Answer:

70000, 6%

Step-by-step explanation:

let the principal be talking P

and rate of interest be r % p. a

Time = 2 yr

Attachments:
Answered by Itzheartcracer
7

Given :-

If  the simple intrest and compound interest of of certian sum of money for two years are RS. 8400 and RS. 8652

To Find :-

Sum of money

Rate

Solution :-

Let the principal be p

And rate be r

SI = PRT/100

SI = p × r × 2/100

SI = 2pr/100(1)

Now

CI = P{(1 + r/100)ⁿ - 1}

CI = p{(1 + r/100)² - 1}

CI = p{1 + 2r/100 + r²/(100)² - 1}

CI = p{1 - 1 + 2r/100 + r²/100²}

CI = p{2r/100 + r²/100²}

Taking 100 and r as common

CI = pr/100(2 + r/100) (2)

Now We may divide both equations

{pr/100(2 + r/100)}/{2pr/100} = 8652/8400

{2 + r/100}/{2/100} = 4326/4200

{2 + r/100} = 4326/4200 × 2

r/100 = 4326/2100 - 2

r/100 = 4326 - 4200/2100

r/100 = 126/2100

r = 126/2100 × 100

r = 12600/2100

r = 6%

Now

Using 1

8400 = p × r × 2/100

8400 = p × 6 × 2/100

8400 = p × 12/100

8400 = p × 3/25

8400 × 25/3 = p

2800 × 25 = p

70000 = p

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