if sin 0=3/5 then find cose 0
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csc
θ
=
5
3
cos
θ
=
4
5
,
sec
θ
=
5
4
tan
θ
=
3
4
,
cot
θ
=
4
3
Explanation:
https://www.mathopenref.com/triangle345.html
https://www.mathopenref.com/triangle345.html
sin
θ
=
(Oppo. side) /( Hypotenuse)
=
3
5
According to Pythagorus Theorem,
Adj. side
A
B
=
√
(
A
C
)
2
−
(
B
C
)
2
=
√
5
2
−
3
2
=
4
Any triangle whose sides are in the ratio 3:4:5 is a right triangle.
Such triangles that have their sides in the ratio of whole numbers are called
Pythagorean Triples.
There are an infinite number of them, and this is just the smallest.
csc
θ
=
1
sin
θ
=
5
3
cos
θ
=
A
B
A
C
=
4
5
sec
θ
=
1
cos
θ
=
5
4
tan
θ
=
B
C
A
B
=
3
4
cot
θ
=
1
tan
θ
=
4
3
θ
=
5
3
cos
θ
=
4
5
,
sec
θ
=
5
4
tan
θ
=
3
4
,
cot
θ
=
4
3
Explanation:
https://www.mathopenref.com/triangle345.html
https://www.mathopenref.com/triangle345.html
sin
θ
=
(Oppo. side) /( Hypotenuse)
=
3
5
According to Pythagorus Theorem,
Adj. side
A
B
=
√
(
A
C
)
2
−
(
B
C
)
2
=
√
5
2
−
3
2
=
4
Any triangle whose sides are in the ratio 3:4:5 is a right triangle.
Such triangles that have their sides in the ratio of whole numbers are called
Pythagorean Triples.
There are an infinite number of them, and this is just the smallest.
csc
θ
=
1
sin
θ
=
5
3
cos
θ
=
A
B
A
C
=
4
5
sec
θ
=
1
cos
θ
=
5
4
tan
θ
=
B
C
A
B
=
3
4
cot
θ
=
1
tan
θ
=
4
3
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