Math, asked by krishnachattu9591105, 6 months ago

If sin 0 = 6/10, find, without using table, the value
of (cos 0 + tan 0).

Answers

Answered by angadsingh1709
2

Answer:

31/20

Step-by-step explanation:

heta is written as @

if sin@ = 6/10 = 3/5

then, let height = 3x and hypotenuse=5x

by Pythagoras theorem,

base^2 =25x^2 - 9x^2

base= 4x

So,

cos@ = base/hypotenuse  = 4x/5x = 4/5

and

tan@ =height/base = 3x/4x = 3/4

Thus.

on adding cos@ and tan theta@, they will

4/5 + 3/4

taking LCM,

(16+15)/20 =31/20

pls mark me the brainliest

Answered by akuldas19
0

Step-by-step explanation:

 \cos(x)  =  \sqrt{1 -  { \sin(x) }^{2} }  \\  \:  \:  =   \sqrt{1 -  {( \frac{3}{5}) }^{2} }  \:  =  \frac{4}{5}  \\  \tan(x)  =  \frac{ \sin(x \ ) }{ \cos(x) }  =  \frac{3}{4}

I hope it will help you to understand the solution ☺️

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