Question

If sinθ=0.6 , then sin2θ=​

Answer 1

Answer:

Step-by-step explanation:

we know that sin2Ф=2sinФcosФ

so we have to find cosФ

ok we know sinФ=0.6 which can also be written as 6/10

so we know that sinФ can also be equal to perpendicular/hypotenuse in a right-angled triangle.

so considering a right-angled triangle,perpendicular will be equal to 6 and hypotenuse will be equal to 10

so now,we can find the base=root of (10)²-(6)²=root of 100-36=root of 64=8

so now we can write the cosФ=base/hypotenuse=8/10=0.8

so sin2Ф=2×0.6×0.8=0.96

so sin2Ф=0.96

hope this helps you

thanks,pls mark as the brainliest if u please

Answer 2

Let theta = α Sin α = 0.6 = 3/5=perpendicular/hypotenuse Therefore base = 4 (from pythagoras theorem) Cos α = base/ hypotenuse = 4/5 We know, Sin 2α = 2 sin α cos α = 2 ×0.6×0.8 = 0.96