Question

If sin 0 =8/9, find sin 0 + cos 0​

Answer 1

Answer:

8√17/9

Step-by-step explanation:

Sin 0 = 8/9 ----- given

sin20 + cos20 = 1 ------ Identity

[8/9]2 + cos20 = 1

64/81 + cos20 = 1

cos20= 1-64/81

cos20 = 81-64/81

cos20= 17/81

cos0 = √17/9

sin0 + cos0 = 8/9 + √17/9

sin0 + cos0 = 8√17/9

Answer 2

Given that :

Sin 0 = 8/9 ........1

We know :

Sin 0 = P/H and Cos 0 = B/H

B = root(H^2-P^2) [ Pythagoras theorem)

Now,

B = root(H^2-P^2)

or, B = root(9^2 - 8^2)

or, B = root(81-64)

B = root(17)

Cos 0 = B/H

or, Cos 0 = root(17)/9..........2

Finally,

Sin 0 + Cos 0 = 8/9 + root(17)/9

or, Sin 0 + Cos 0 = 8+root(17)/9. Answer .