If sin 0 and cos 0 are roots of equation ax +bx+c=0 then b²-2аc =?
1) - a?
2) b?
3) a?
4)-b*2
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Answer:
ax
2
−bx+c=0
sinθ and cosθ are roots.
∴sinθ+cosθ=
a
b
;sinθ cosθ=
a
c
Then (sinθ+cosθ)=
a
2
b
2
or sin
2
θ+cos
2
θ+2sinθcosθ=
a
2
b
2
or 1+2
a
c
=
a
2
b
2
or
a
a+2c
=
a
2
b
2
or
a
a+2c
×a
2
=b
2
or (a+2c)a=b
2
or a
2
+2ac=b
2
or a
2
−b
2
+2ac=0
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