Math, asked by SukhpreetSidhu66, 2 months ago

If sin 0 and cos 0 are roots of equation ax +bx+c=0 then b²-2аc =?
1) - a?
2) b?
3) a?
4)-b*2​

Answers

Answered by reddysandhya39322
1

Answer:

ax

2

−bx+c=0

sinθ and cosθ are roots.

∴sinθ+cosθ=

a

b

;sinθ cosθ=

a

c

Then (sinθ+cosθ)=

a

2

b

2

or sin

2

θ+cos

2

θ+2sinθcosθ=

a

2

b

2

or 1+2

a

c

=

a

2

b

2

or

a

a+2c

=

a

2

b

2

or

a

a+2c

×a

2

=b

2

or (a+2c)a=b

2

or a

2

+2ac=b

2

or a

2

−b

2

+2ac=0

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