Question

If sin 0 + cos 0 = √2 cos 0, 0° << 90°, then write the value of cot .​

Answer 1

HELLO DEAR,

LET THETA = ALPHA

$\begin{gathered} \sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \cos( 90 - \alpha ) \\ \\ \sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \sin( \alpha ) \\ \\ \cos( \alpha ) = \sqrt{2} \sin( \alpha ) - \sin( \alpha ) \\ \\ \cos( \alpha ) = \sin \alpha ( \sqrt{2} - 1) \\ \\ \frac{ \cos( \alpha ) }{ \sin( \alpha ) } = ( \sqrt{2} - 1) \\ \\ \cot( \alpha ) = ( \sqrt{2} - 1)\end{gathered}$

I HOPE ITS HELP YOU DEAR,

THANKS