Question

If sin 0 + cos 0 = √2 sin (90° - 0). then find cos 0.

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Answer 1

Step-by-step explanation:

your answer is in attachment

Answer 2

Answer:

Hey Mate, Good evening ❤

#Here's ur answer..☆☆☆

Step-by-step explanation:

$\boxed{ \huge{ \red{theta = \alpha }}}$

$\bold{ \green{given \: ...}} \bold{ \sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \sin(90 - \alpha ) } \\ \bold{to \: find \: \cos( \alpha ) }$

$= > \sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \sin(90 - \alpha ) \\ = > \sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \cos( \alpha ) \\ ( \bold{ \red{ \sin(90 - \alpha ) = \cos( \alpha ) }}) \\ = > \sin( \alpha ) = \sqrt{2} \cos( \alpha ) - \cos( \alpha ) \\ = > \sin( \alpha ) = \cos( \alpha ) ( \sqrt{2} - 1) \\ = > \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \sqrt{2} - 1 \\ = > \frac{ \cos( \alpha ) }{ \sin( \alpha ) } = \frac{1}{ \sqrt{2} - 1} \\ = \frac{( \sqrt{2} + 1)}{( \sqrt{2} - 1)( \sqrt{2} + 1) } = \sqrt{2} + 1 (\blue{answer})$

$\cot( \alpha ) = \sqrt{2} + 1$

➡️Hope this helps you..✌✌

➡️Pls mark as brainliest..❇❇❇

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