Question

If sin 0 - cos 0 = 3/5 then sin 0 cos 0 =
(a) 16/25 (b) 9/16 (c) 9/25 (d)8/25​

Answer 1

Answe

The answer is option (d)

Answer 2

Answer:

( d ) 8 / 25

Step-by-step explanation:

Given-----> Sinθ - Cosθ = 3/5

To find -----> Sinθ Cosθ = ?

Solution------> ATQ,

Sinθ - Cosθ = 3 / 5

Squaring both sides we get,

=> ( Sinθ - Cosθ )² = ( 3 / 5 )²

We know that,

( a - b )² = a² + b² - 2ab , applying it , we get,

=> Sin²θ + Cos²θ - 2 Sinθ Cosθ = 9 / 25

We know that, Sin²A + Cos²A = 1 , applying it we get,

=> ( Sin²θ + Cos²θ ) - 2 Sinθ Cosθ = 9 / 25

=> 1 - 2 Sinθ Cosθ = 9 / 25

=> - 2 Sinθ Cosθ = ( 9 / 25 ) - 1

=> - 2 Sinθ Cosθ = ( 9 - 25 ) / 25

=> - 2 Sinθ Cosθ = - 16 / 25

Changing sign of both sides

=> 2 Sinθ Cosθ = 16 / 25

=> Sinθ Cosθ = 16 / 50

=> Sinθ Cosθ = 8 / 25